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6a^2+9a-27=0
a = 6; b = 9; c = -27;
Δ = b2-4ac
Δ = 92-4·6·(-27)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-27}{2*6}=\frac{-36}{12} =-3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+27}{2*6}=\frac{18}{12} =1+1/2 $
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